t=sinα+cosα且(sinα)^3+(cosα)^3＜0,求t的取值范圍.
t=sinα+cosα且(sinα)^3+(cosα)^3＜0,求t的取值范圍.
數(shù)學(xué)人氣：846 ℃時(shí)間：2020-10-01 13:14:39
優(yōu)質(zhì)解答
t=根號(hào)2sin(a+45度） -根號(hào)2
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