①、當(dāng)x=2時(shí),代入拋物線的右邊得到4a-2b+3=2(2a-b)+3=-2+3=1,故①正確;
②、由題意得b=2a+1,由對(duì)稱軸x=-
b |
2a |
2a+1 |
2a |
③、由2a-b=-1得到:b=2a+1.拋物線的頂點(diǎn)坐標(biāo)公式可知縱坐標(biāo)
4ac?b2 |
4a |
12a?b2 |
4a |
12a?(2a+1)2 |
4a |
| ||
a |
(?a)? (?
|
故選C.
b |
2a |
2a+1 |
2a |
4ac?b2 |
4a |
12a?b2 |
4a |
12a?(2a+1)2 |
4a |
| ||
a |
(?a)? (?
|