(a1a2...an)^(1/n)≤(a1+a2+...+an)/n
2邊n次方 得到 a1a2...an)≤[(a1+a2+...+an)/n]^n
等號成立 當(dāng)且僅當(dāng) a1=a2=……=an成立
后面詳細(xì)的看圖片吧,圖片上很詳細(xì),這里不好打格式
(1+1/n)^n=(1+1/n)^n * 1 = (1+1/n)(1+1/n)...(1+1/n)*1
< {1/(n+1)[(1+1/n)+……+(1+1/n)+1] }^(n+1)
={1/(n+1)[(1+1/n)*n+1] }^(n+1)
=[1+1/(n+1)]^(n+1)
