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  • 1.已知sin(π/4-α)=3/5,π/4-α為第二象限角,求sin(α-13π/4)+sin(α+21π/4)的值

    1.已知sin(π/4-α)=3/5,π/4-α為第二象限角,求sin(α-13π/4)+sin(α+21π/4)的值
    2.已知y=a-bcos(3x-π/2的最大值為6,最小值為-2,求實(shí)數(shù)a,b的值
    數(shù)學(xué)人氣:617 ℃時(shí)間:2020-09-05 03:40:51
    優(yōu)質(zhì)解答
    1
    sin(π/4-α)=3/5
    π/4-α為第二象限角
    cos(π/4-α)=-根號(hào)[1-sin^2(π/4-α)]=-根號(hào)[1-(3/5)^2] = -4/5
    sin(α-13π/4)+sin(α+21π/4)
    =sin(-4π+π+α-π/4)+sin(4π+π+α+π/4)
    =sin(π+α-π/4)+sin(π+α+π/4)
    =-sin(α-π/4)-sin(α+π/4)
    =sin(π/4-α)-cos(π/2-α-π/4)
    =sin(π/4-α)-cos(π/4-α)
    =3/5-(-4/5)
    =8/5
    2.
    y=a-bcos(3x-π/2)
    -1≤ cos(3x-π/2) ≤ 1
    當(dāng)b>0時(shí):
    最小值a-b=-2,最大值a+b=6
    a=2,b=4
    當(dāng)b<0時(shí):
    最小值a+b=-2,最大值a-b=6
    a=2,b=-4
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