an=2^n
步驟：
等比數(shù)列{an},=>an=a1*q^(n-1),(a1、q不為0)
=> a2=a1q,a3=a1q^2,a4=a1q^3,
2a1+a3=3a2
=>2a1+a1q^2=3a1q,=> q^2-3q+2=0,=>q=1或2,
a3+2是a2,a4的等差中項(xiàng),=>2(a3+2)=a2+a4,=>2a1q^2+4=a1q+a1q^3,
1) q=1時(shí),=> 2a1+4=a1+a1,=>不成立.
2) q=2時(shí),=> 2a1*4+4=a1*2+a1*8,=> a1=2,
=> an=a1*q^(n-1)=2*2^(n-1)=2^n.