ylnx=xlny
對(duì)x求導(dǎo)
y'*lnx+y*1/x=x'*lny+x*(1/y)*y'
y'*lnx+y/x=lny+y'*x/y
y'(lnx-x/y)=lny-y/x(xlny-y)/x
y'(ylnx-x)/y=(xlny-y)/x
所以y'=y(xlny-y)/[x(ylnx-x)]
高數(shù)達(dá)人來啊!隱函數(shù)
高數(shù)達(dá)人來啊!隱函數(shù)
x^y=y^x 求隱函數(shù)的導(dǎo)數(shù)
x^y=y^x 求隱函數(shù)的導(dǎo)數(shù)
數(shù)學(xué)人氣：161 ℃時(shí)間：2020-07-03 03:05:51
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