①,已知f(x)= | lg(x-1)|,所以相當(dāng)于把y=lg（x-1）在x軸以下的圖像翻著到x軸上方,呈對(duì)稱且由題可知,當(dāng)x=2時(shí),f（x）=0所以同一個(gè)y值是可有2個(gè)x值對(duì)應(yīng)的當(dāng)實(shí)數(shù)a,b滿足14==>a-1>1a>2,與a4(b-1)=(a-1)^2+(b-1)^2+2,10解...第一問如何解釋∵f(a)= f(b/(b-1)),|lg(a-1)|=|lg(b/(b-1)-1)|=|lg1/(b-1)|故f(a)、f(b/(b-1))的圖象一致，對(duì)實(shí)數(shù)a,b滿足1