A是除以2余數(shù)是1的整數(shù),顯然就是奇數(shù)
B是除以3余數(shù)是1的整數(shù)
即3的倍數(shù)加1
若3的倍數(shù)是奇數(shù),則加1是偶數(shù),不屬于A
若3的倍數(shù)是偶數(shù),則加1是奇數(shù),屬于A
3的倍數(shù)是偶數(shù),則能被2和3整除,即6的倍數(shù)
所以A交B=|z|z=6k+1,k是整數(shù)}