f(x)=-x^2+2mx=-(x-m)^2+m^2開口向下
在區(qū)間[1.2]上是減函數(shù)
即對稱軸x=m≤1
g(x)=m/x+1在區(qū)間[1.2]上是減函數(shù)
即m>0
所以0
若f(x)=-x2+2mx與g(x)=m/x+1在區(qū)間[1.2]上都是減函數(shù),求m的取值范圍
若f(x)=-x2+2mx與g(x)=m/x+1在區(qū)間[1.2]上都是減函數(shù),求m的取值范圍
數(shù)學(xué)人氣：651 ℃時(shí)間：2019-10-23 05:54:07
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