將右邊的項移到左邊,得1/(a-1)-1/(3-2a)<0
通分得(2-3a)/((a-1)(3-2a))<0
等價于(a+1)(3a-2)(2a-3)<0
解得a<-1或2/3
若1/(a-1)
若1/(a-1)<1/(3-2a),則實數(shù)a的取值范圍
怎么把上式化成(a+1)(3a-2)(2a-3)<0的?
怎么把上式化成(a+1)(3a-2)(2a-3)<0的?
數(shù)學(xué)人氣：813 ℃時間：2020-05-05 05:07:29
優(yōu)質(zhì)解答
1/(a-1)<1/(3-2a),
將右邊的項移到左邊,得1/(a-1)-1/(3-2a)<0
通分得(2-3a)/((a-1)(3-2a))<0
等價于(a+1)(3a-2)(2a-3)<0
解得a<-1或2/3
將右邊的項移到左邊,得1/(a-1)-1/(3-2a)<0
通分得(2-3a)/((a-1)(3-2a))<0
等價于(a+1)(3a-2)(2a-3)<0
解得a<-1或2/3
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