x/(x^2+2x+1)
=x/(x+1)^2
=x^2(x-1)/[x(x+1)^2(x-1)]
=(x^3-x^2)/[x(x+1)^2(x-1)]
(x-1)/(x^2+x)
=(x-1)/[x(x+1)]
=(x-1)^2(x+1)//[x(x+1)^2(x-1)]
=(x^3-x^2-x+1)/[x(x+1)^2(x-1)]
1/(x^2-1)
=1/[(x+1)(x-1)]
=x(x+1)/[x(x+1)^2(x-1)]
=(x^2+x)/[x(x+1)^2(x-1)]
通分:(1)x/x^2+2x+1,(2)x-1/x^2+x,(3)1/x^2-1
通分:(1)x/x^2+2x+1,(2)x-1/x^2+x,(3)1/x^2-1
數(shù)學(xué)人氣:988 ℃時間:2020-05-10 09:37:18
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