令u屬于[1,3]
又f(x)在R上周期為2
所以f(u)=f(u-2)=(u-2)^2
所以f(x)當x∈【1,3】時,表達式為(x-2)^2求f(-3)f(3.5)的值f(-3)=f(1-2*2)=f(1)=1f(3.5)=f(1.5+2)=f(1.5)=2.25
f(x)是定義域在R上,以2為周期的函數(shù),當x∈【-1,1】時f(x)=x2 (1) 求x∈【1,3】時,f(x)的表達式 (2)
f(x)是定義域在R上,以2為周期的函數(shù),當x∈【-1,1】時f(x)=x2 (1) 求x∈【1,3】時,f(x)的表達式 (2)
數(shù)學人氣:226 ℃時間:2020-01-31 03:30:12
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