精品偷拍一区二区三区,亚洲精品永久 码,亚洲综合日韩精品欧美国产,亚洲国产日韩a在线亚洲

  • <center id="usuqs"></center>
  • 
    
  • 已知x2-8x+y2-y+161/4=0,求[(x+y)(x-y)-(x+y)2-2y(x-3y)]÷4y的值.

    已知x2-8x+y2-y+16
    1
    4
    =0,求[(x+y)(x-y)-(x+y)2-2y(x-3y)]÷4y的值.
    數(shù)學(xué)人氣:191 ℃時(shí)間:2020-05-02 06:36:41
    優(yōu)質(zhì)解答
    x2-8x+y2-y+16
    1
    4
    =0,
    (x-4)2+(y-
    1
    2
    2=0,
    x-4=0,y-
    1
    2
    =0,
    x=4,y=
    1
    2
    ,
    [(x+y)(x-y)-(x+y)2-2y(x-3y)]÷4y
    =[x2-y2-x2-y2-2xy-2xy+6y2]÷4y
    =[4y2-4xy]÷4y
    =y-x
    =
    1
    2
    -4
    =-3
    1
    2
    我來回答
    類似推薦
    請(qǐng)使用1024x768 IE6.0或更高版本瀏覽器瀏覽本站點(diǎn),以保證最佳閱讀效果。本頁提供作業(yè)小助手,一起搜作業(yè)以及作業(yè)好幫手最新版!
    版權(quán)所有 CopyRight © 2012-2024 作業(yè)小助手 All Rights Reserved. 手機(jī)版