令 f'(x)=-x^2+4ax=0,解得x1=0,x2=4a
則(1)x>=4a時(shí),f'(x)<0,f(x)為減函數(shù)
(2)0
(3)x<=0時(shí),f'(x)<0,f(x)為減函數(shù)
若a<=x<=2時(shí)
則(1)當(dāng)1>a>1/2時(shí),此時(shí)0(2)當(dāng)1/2>=a>0時(shí),此時(shí)0=(根號(hào)2)/8或者a>=-(根號(hào)2)/8,此時(shí)交集為1/2>=a>=(根號(hào)2)/8
上述a的范圍的并集即為所求:1/2>=a>=(根號(hào)2)/8