6.5g鋅與一定量的7.3%稀鹽酸恰好完全反應(yīng),求鹽酸的溶質(zhì)質(zhì)量及反應(yīng)后氯化鋅溶液的溶質(zhì)質(zhì)量分?jǐn)?shù).

化學(xué)人氣：534 ℃時間：2019-11-06 06:15:00

優(yōu)質(zhì)解答

設(shè)鹽酸的溶質(zhì)質(zhì)量為x,生成ZnCl2的質(zhì)量為y,生成H2的質(zhì)量為z.
Zn+2HCl=ZnCl2+H2↑
65 73 136 2
6.5g x y z
65/6.5=73/x=136/y=2/z
x=7.3g
y=13.6g
z=0.2g
鹽酸的質(zhì)量是7.3/7.3%=100g
反應(yīng)后溶液質(zhì)量是6.5+100-0.2=106.3g
氯化鋅溶液的溶質(zhì)質(zhì)量分?jǐn)?shù)是13.6/106.3*100%=12.8%
答：鹽酸的溶質(zhì)質(zhì)量是7.3g,反應(yīng)后氯化鋅溶液的溶質(zhì)質(zhì)量分?jǐn)?shù)是12.8%