sin^4x+cos^4x=5/9
(sin^2x+cos^2x)^2-2sin^2xcos^2x=5/9
1-sin^2(2x)/2=5/9
sin^2(2x)=8/9
sin2X=正負(fù)2根號2/3
sin^4x+cos^4x=5/9 求sin2X
sin^4x+cos^4x=5/9 求sin2X
解答過程
解答過程
數(shù)學(xué)人氣:111 ℃時間:2020-02-22 20:55:48
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