若使得方程16?x2-x-m=0有實數(shù)解,則實數(shù)m的取值范圍為( ) A.-42≤m≤42 B.-4≤m≤42 C.-4≤m≤4 D.4≤m≤42
若使得方程
-x-m=0有實數(shù)解,則實數(shù)m的取值范圍為( ?。?br/>A. -4
≤m≤4
B. -4≤m≤4
C. -4≤m≤4
D. 4≤m≤4
數(shù)學人氣:255 ℃時間:2019-08-21 16:55:31
優(yōu)質解答
-x-m=0可化為
=x+m,即問題轉化為y=
與y=x+m有公共點
做出函數(shù)圖象:
容易算出當直線y=x+m與半圓相切時m=4
,當直線過(4,0)點時m=-4.
故m的范圍是
?4≤m≤4.
故選B.
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