設(shè)根號(hào)下x-1=a 則a≥0
x-1=a² x=a²+1
f(x)=a²+1+a
=a²+a+1/4+3/4
=(a+1/2)²+3/4
∵a≥0 ∴(a+1/2)²≥1/4
f(x)≥1
函數(shù)的最小值為1,此時(shí)x=1
求f(x)=x+根號(hào)下x-1內(nèi)最小值
求f(x)=x+根號(hào)下x-1內(nèi)最小值
數(shù)學(xué)人氣:596 ℃時(shí)間:2020-01-28 07:52:09
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