y1與x-3成正比例,y2與x+8成反比例y1=k1(x-3)y2與x+8成反比例y2=k2/(x+8)已知y=2y1-3y2y=2k1(x-3)-3k2/(x+8)當(dāng)x=1時(shí),y=-3,-3=2k1(1-3)-3k2/(1+8)-3=-4k1- k2/312k1+k2=9 (1)當(dāng)x=5時(shí),y=-11-11=2k1(5-3)-3k2/(5+8)-11=4...額，前面打錯(cuò)了，當(dāng)x=-5時(shí)，y=-11y1與x-3成正比例,y2與x+8成反比例y1=k1(x-3)y2與x+8成反比例y2=k2/(x+8)已知y=2y1-3y2y=2k1(x-3)-3k2/(x+8)當(dāng)x=1時(shí),y=-3,-3=2k1(1-3)-3k2/(1+8)-3=-4k1- k2/312k1+k2=9 (1)當(dāng)x=-5時(shí)，y=-11-11=2k1(-5-3)-3k2/(-5+8)-11=-16k1- k216k1+k2=11 (2)由(2)-(1)得4k1=2k1=1/2k2=3y關(guān)于x的函數(shù)解析式y(tǒng)=(x-3) - 9/(x+8)