由拋物線方程可知兩交點(diǎn)坐標(biāo)為(-3,0)(-m,0)
∵OA:OB=3:1 OA=3
∴OB=1
∴B點(diǎn)坐標(biāo)為(-1,0)或(1,0)
∴m=±1
拋物線y=2(x+3)(x+m)與X軸交與A,B兩點(diǎn)(A在B的左側(cè))且OA:OB=3:1,求m的值
拋物線y=2(x+3)(x+m)與X軸交與A,B兩點(diǎn)(A在B的左側(cè))且OA:OB=3:1,求m的值
數(shù)學(xué)人氣:703 ℃時(shí)間:2019-08-22 10:04:42
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