化簡求值：2cosˆ210°-tan5°（1+cos10°）-2sin40°sin80°
化簡求值：2cosˆ210°-tan5°（1+cos10°）-2sin40°sin80°
數(shù)學人氣：745 ℃時間：2020-07-29 14:28:48
優(yōu)質解答
2(cos10°)^2-tan5°（1+cos10°）-2sin40°sin80° =cos20°+1-sin5°/cos5°*(1+2(cos5°)^2-1)-(cos(40°-80°)-cos(40°+80°))=cos20°+1-2sin5°*cos5°-cos40°+cos120°=cos20°-sin10°-cos40°+1/2=cos20...
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