第一道題通式為：an = an-1 + (-1)^(n-1) / (2^(n-1)),(a1=1/2,n>=2)
可得 a2 = 1/2 + (-1)^1 / (2^1) = 1/2 - 1/2 = 0;
a3 = 0 + (-1)^2 / (2^2) = 0 + 1/4 = 1/4;
a4 = 1/4 + (-1)^3 / (2^3) = 1/4 - 1/8 = 1/8;
a5 = 1/8 + (-1)^4 / (2^4) = 1/8 + 1/16 = 3/16;
因此第一道題的答案就是：3/16
第二道題通式為：an = an-1 + 2 + (n-2)^2,(a1=1,n>=2)
可得 a2 = 1 + 2 + (2-2)^2 = 1 + 2 + 0 = 3;
a3 = 3 + 2 + (3-2)^2 = 3 + 2 + 1 = 6;
a4 = 6 + 2 + (4-2)^2 = 6 + 2 + 4 = 12;
a5 = 12 + 2 + (5-2)^2 = 12 + 2 + 9 = 23;
a6 = 23 + 2 + (6-2)^2 = 23 + 2 + 16 = 41;
因此第二道題的答案就是：23
都兩點鐘了,終于解決了