2x+3 |
x?1 |
∴f-1(x)=
x+3 |
x?2 |
∵函數(shù)y=g(x)的圖象與y=f-1(x)+1的圖象關(guān)于直線y=x對稱,
∴函數(shù)y=g(x)與函數(shù)y=f-1(x)+1互為反函數(shù),
又∵函數(shù)y=f-1(x)+1=
x+3 |
x?2 |
y=
2x+1 |
x?2 |
即g(x)=
2x+1 |
x?2 |
則g(3)=
2×3+1 |
3?2 |
故答案為:7.
2x+3 |
x?1 |
2x+3 |
x?1 |
x+3 |
x?2 |
x+3 |
x?2 |
2x+1 |
x?2 |
2x+1 |
x?2 |
2×3+1 |
3?2 |