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  • 利用乘法公式計(jì)算

    利用乘法公式計(jì)算
    (x+y)(x²+y²)(x-y)(x的四次方+y四次方)
    (a-2b+3)(a+2b-3)
    [(x-y)²+(x+y)²](x²-y²)
    (m-n-3)²
    先化簡(jiǎn),再求值
    [(a-1/2)²-(a+1/2)²](a+3),其中a=-2
    數(shù)學(xué)人氣:827 ℃時(shí)間:2020-01-27 02:05:40
    優(yōu)質(zhì)解答
    (x+y)(x²+y²)(x-y)(x的四次方+y四次方)
    = (x + y)(x - y)(x^2 + y^2)(x^4 + y^4)
    = (x^2 - y^2)(x^2 + y^2)(x^4 + y^4)
    = (x^4 - y^4)(x^4 + y^4)
    = x^8 - y^8
    (a-2b+3)(a+2b-3)
    = [a - (2b - 3)][a + (2b - 3)]
    = a^2 - (2b - 3)^2
    = a^2 - 4 b^2 + 12 b - 9
    [(x-y)²+(x+y)²](x²-y²)
    = 2 (x^2 + y^2)(x^2 - y^2)
    = 2 (x^4 - y^4)
    = 2 x^4 - 2 y^4
    (m-n-3)²
    = m^2 + n^2 + 9 - 2 m n - 6 m + 6n
    [(a-1/2)²-(a+1/2)²](a+3)
    = [(a - 1/2)+(a + 1/2)][(a - 1/2)-(a + 1/2)](a + 3)
    = 2 a (-1) (a + 3)
    = - 2 a^2 - 6 a
    將 a = -2 代入,得
    [(a-1/2)²-(a+1/2)²](a+3)
    = -2 * (-2)^2 - 6 * (-2)
    = 4
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