則
|
|
∵y′=f(x′)=
2x′ |
x′+1 |
∴y=
2(4-x) |
4-x+1 |
8-2x |
5-x |
2x-8 |
x-5 |
故g(x)=
2x-8 |
x-5 |
(2)∵Φ(x+2)=
1 |
Φ(x) |
∴Φ(x+4)=
1 |
Φ(x+2) |
即Φ(x)是周期為4的周期函數(shù),
則Φ(2005)=Φ(2004+1)=Φ(1)=Φ(-3)=
1 |
Φ(-3+2) |
1 |
Φ(-1) |
1 |
g(-1) |
1 | ||
|
6 |
10 |
3 |
5 |
故Φ(2005)=
3 |
5 |
2x |
x+1 |
1 |
Φ(x) |
|
|
2x′ |
x′+1 |
2(4-x) |
4-x+1 |
8-2x |
5-x |
2x-8 |
x-5 |
2x-8 |
x-5 |
1 |
Φ(x) |
1 |
Φ(x+2) |
1 |
Φ(-3+2) |
1 |
Φ(-1) |
1 |
g(-1) |
1 | ||
|
6 |
10 |
3 |
5 |
3 |
5 |