精品偷拍一区二区三区,亚洲精品永久 码,亚洲综合日韩精品欧美国产,亚洲国产日韩a在线亚洲

  • <center id="usuqs"></center>
  • 
    
  • 求數(shù)列{n^2*2^n}的前n項(xiàng)和(高二數(shù)列問(wèn)題)

    求數(shù)列{n^2*2^n}的前n項(xiàng)和(高二數(shù)列問(wèn)題)
    注意啊 是n的平方再乘以2的n次方啊
    數(shù)學(xué)人氣:958 ℃時(shí)間:2019-09-03 01:06:43
    優(yōu)質(zhì)解答
    a(n) = n^2*2^n = n(n+1)2^n - n2^n = b(n) - c(n).
    C(n) = c(1)+c(2)+c(3) + ... + c(n-1) + c(n)
    = 1*2 + 2*2^2 + 3*2^3 + ... + (n-1)2^(n-1) + n2^n
    2C(n) = 1*2^2 + 2*2^3 + ... + (n-1)2^n + n2^(n+1),
    C(n) = 2C(n) - C(n) = - 2 - 2^2 - 2^3 - ... - 2^n + n2^(n+1)
    = n2^(n+1) - 2[1 + 2 + ... + 2^(n-1)]
    = n2^(n+1) - 2[2^n - 1]/(2-1)
    = n2^(n+1) - 2^(n+1) + 2
    = 2 + (n-1)2^(n+1).
    B(n) = b(1)+b(2)+b(3) + ... + b(n-1) + b(n)
    = 1*2*2^1 + 2*3*2^2 + 3*4*2^3 + ... + (n-1)n2^(n-1) + n(n+1)2^n
    2B(n) = 1*2*2^2 + 2*3*2^3 + ... + (n-1)n2^n + n(n+1)2^(n+1),
    B(n) = 2B(n) - B(n) = -2*1*2^1 - 2*2*2^2 - 2*3*2^3 - ... - 2*n*2^n + n(n+1)2^(n+1)
    = n(n+1)2^(n+1) - 2[1*2^1 + 2*2^2 + 3*2^3 + ... + n*2^n]
    = n(n+1)2^(n+1) - 2C(n)
    s(n) = a(1)+a(2)+...+a(n) = b(1)+b(2)+...+b(n) - c(1) - c(2) - ... - c(n) = B(n) - C(n)
    = n(n+1)2^(n+1) - 2C(n) - C(n)
    = n(n+1)2^(n+1) - 3C(n)
    = n(n+1)2^(n+1) - 3[2 + (n-1)2^(n+1)]
    = n(n+1)2^(n+1) - 6 - 3(n-1)2^(n+1)
    = [n^2 + n - 3n + 3]2^(n+1) - 6
    = [n^2 - 2n+3]2^(n+1) - 6
    我來(lái)回答
    類似推薦
    請(qǐng)使用1024x768 IE6.0或更高版本瀏覽器瀏覽本站點(diǎn),以保證最佳閱讀效果。本頁(yè)提供作業(yè)小助手,一起搜作業(yè)以及作業(yè)好幫手最新版!
    版權(quán)所有 CopyRight © 2012-2024 作業(yè)小助手 All Rights Reserved. 手機(jī)版