25(x+2)^2-30(x+2)+9=0
提出25,則25[(x+2)^2-6/5(x+2)+9/25-9/25]+9=0
25[(x+2)^2-6/5(x+2)+9/25]-25*9/25+9=0
25(x+2-3/5)^2=0
(x+2-3/5)^2=0
x+2-3/5=0
x=-7/5
25(x+2)^2-30(x+2)+9=0
25(x+2)^2-30(x+2)+9=0
數(shù)學(xué)人氣:948 ℃時(shí)間:2020-03-28 04:28:25
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