分解因式 a^4+b^4+c^4-2a^2b^2-2a^2c^2-2b^2c^2
分解因式 a^4+b^4+c^4-2a^2b^2-2a^2c^2-2b^2c^2
數(shù)學(xué)人氣:721 ℃時間:2019-10-23 11:21:03
優(yōu)質(zhì)解答
a^4+b^4+c^4-2a^2b^2-2a^2c^2-2b^2c^2=(a^2-b^2-c^2)^2-4b^2c^2=(a^2-b^2-c^2+2bc)(a^2-b^2-c^2-2bc)=[a^2-(b^2-2bc+c^2)][a^2-(b^2+2bc+c^2)]=[a^2-(b-c)^2][a^2-(b+c)^2] =(a+b-c)(a-b+c)(a+b+c)(a-b-c)...
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