解
y=x/(e^x)
y'=[x'(e^x)-x(e^x)']/(e^x)²
=(e^x-xe^x)/e^2x
y=x/(e^x)求導(dǎo),
y=x/(e^x)求導(dǎo),
如題
如題
數(shù)學(xué)人氣：206 ℃時間：2020-04-10 02:15:47
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