若偶函數(shù)y=f(x)是最小正周期為2的周期函數(shù),且當(dāng)2≤x≤3時(shí)f(X)=X,則當(dāng)-2≤x≤0時(shí)f(x)的解析式為__
若偶函數(shù)y=f(x)是最小正周期為2的周期函數(shù),且當(dāng)2≤x≤3時(shí)f(X)=X,則當(dāng)-2≤x≤0時(shí)f(x)的解析式為__
要詳細(xì)解答,越詳細(xì)越好.謝謝.
優(yōu)質(zhì)解答
f(x)=x [2,3]
f(x)=x [0,1]
f(x)=-x [-1,0]
f(x)=-x [1,2]
所以
f(x)=x [-2,-1]
f(x)=-x [-1,0]答案給的是f(x)={4+x,-2≤x≤1;2-x,-1