求給定微分方程的特解
求給定微分方程的特解
求微分方程滿足所給初始條件的特解y'+x^2* y=x^2 ,當(dāng)x=2,y =1
我解得：x=2時(shí)，Y=1。代進(jìn)去后成 LN Y-1=LN0了，這個(gè)沒解了
求微分方程滿足所給初始條件的特解y'+x^2* y=x^2 ,當(dāng)x=2,y =1
我解得：x=2時(shí)，Y=1。代進(jìn)去后成 LN Y-1=LN0了，這個(gè)沒解了
數(shù)學(xué)人氣：623 ℃時(shí)間：2020-10-01 08:18:54
優(yōu)質(zhì)解答
dy/dx+(x^2)y=x^2對(duì)應(yīng)齊次方程為:dy/dx+(x^2)y=0dy/y=-(x^2)dxIny=-(x^3)/3+InCIn(y/C)=-(x^3)/3y=Ce^[-(x^3)/3]=C(x)e^[-(x^3)/3]dy/dx=C'(x)e^[-(x^3)/3]-(x^2)C(x)e^[-(x^3)/3]代入原方程C'(x)e^[-(x^3)/3]-(x^2)...
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