解由f(π/3+x)=f(-x)
知函數(shù)的對(duì)稱軸為x=(π/3)/2=π/6
由x=π/6是函數(shù)f(X)=3sin(ωx+φ)對(duì)稱軸知
f(π/6)=±3.由f(π/3+x)=f(-x)知函數(shù)的對(duì)稱軸為x=[(π/3+x)+（-x）]/2=π/6.這是數(shù)學(xué)方法函數(shù)f（x）滿足f（a+x）=f（b-x）則函數(shù)的對(duì)稱軸為x=[(a+x)+(b-x)]/2=（a+b）/2你先記住這個(gè)結(jié)論吧。