A={(x,y)|x=√2 cosa,y=√2 sina + m,a為參數(shù)}
x=√2 cosa,y=√2 sina + m
==>
x²+(y-m)²=2
A為以C(0,m)圓心,√2為半徑圓上點(diǎn)的集合
B={{x,y)|x=t+3,y=3-t,t為參數(shù)}
x=t+3,y=3-t
==>x+y=6,即x+y-6=0
B為直線x+y-6=0上點(diǎn)的集合
A∩B≠∅,直線與圓C有公共點(diǎn)
∴C到直線距離小于等于半徑
即||m-6|/√2≤√2
∴|m-6|≤2
==>4≤m≤8
希望能幫到你啊,如果你
已知A={(x,y)|x=√2 cosa,y=√2 sina + m,a為參數(shù)}B={{x,y)|x=t+3,y=3-t,t為參數(shù)}且A∩B≠∅,求實(shí)數(shù)m的取值范圍
已知A={(x,y)|x=√2 cosa,y=√2 sina + m,a為參數(shù)}B={{x,y)|x=t+3,y=3-t,t為參數(shù)}且A∩B≠∅,求實(shí)數(shù)m的取值范圍
數(shù)學(xué)人氣:474 ℃時(shí)間:2020-06-02 20:59:59
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