log8(a)+log4(b^2)=5===>1/3*log2(a)+log2(b)=5---------1)
log8(b)+log4(a^2)=7===>1/3*log2(b)+log2(a)=7---------2)
解1）,2）得：
log2(a)=6
log2(b)=3
log4（根號(hào)下ab）=1/4*log2（ab）=1/4×[log2(a)+log2(b)]=9/4
已知已知log8(a)+log4(b^2)=5,log8(b)+log4(a^2)=7,求log4（根號(hào)下ab）
已知已知log8(a)+log4(b^2)=5,log8(b)+log4(a^2)=7,求log4（根號(hào)下ab）
數(shù)學(xué)人氣：554 ℃時(shí)間：2020-06-15 15:23:33
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