極限(1^2+2^2+...+n^2)/(n^3)
=lim(n->∞) [1/6 n(n+1)(2n+1)]/n^3
=lim(n->∞) [1/6 (1/n+1)(2+1/n)]
=1/6 ×1×2
=1/3
數(shù)學(xué),極限(1^2+2^2+...+n^2)/(n^3)是多少?
數(shù)學(xué),極限(1^2+2^2+...+n^2)/(n^3)是多少?
數(shù)學(xué)人氣：131 ℃時(shí)間：2020-06-08 11:43:44
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