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  • 函數(shù)y=sin(x+π/3)的單調(diào)增區(qū)間是

    函數(shù)y=sin(x+π/3)的單調(diào)增區(qū)間是
    函數(shù)y=cos(2x+π/3)的單調(diào)增區(qū)間是
    函數(shù)y=sin(π/3-x)的單調(diào)增區(qū)間是
    數(shù)學(xué)人氣:330 ℃時(shí)間:2020-02-03 17:58:26
    優(yōu)質(zhì)解答
    y=cos(2x+π/3)的單調(diào)增區(qū)間是[kπ-2π/3,kπ-π/6],k∈Z
    由2kπ-π≤2x+π/3≤2kπ,k∈Z
    得kπ-2π/3≤x≤kπ-π/6,k∈Z
    ∴...
    函數(shù)y=sin(π/3-x)的單調(diào)增區(qū)間是[kπ+5π/12,kπ+11π/12],k∈Z
    y=sin(π/3-x)=-sin(x-π/3)
    由2kπ+π/2≤x-π/3≤2kπ+3π/2,k∈Z
    得kπ+5π/12≤x≤kπ+11π/12,k∈Z
    ∴...還有一個(gè),在上面y=sin(x+π/3)的單調(diào)增區(qū)間是[kπ-5π/12.kπ+π/12],k∈Z由2kπ-π/2≤x+π/3≤2kπ+π/2,k∈Z得kπ-5π/12≤x≤kπ+π/12,k∈Z
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