GMm/R^2=mg
GM/R^2=g
GM=gR^2
設(shè)角速度為分布wa,wb
(wa^2)Ra=GM/Ra^2
wa^2=GM/Ra
wb^2=GM/Rb
設(shè)周期Ta,Tb
Ta=2π/wa=2π根號(Ra/GM)
Tb=2π/wb=2π根號(Rb/GM)
2)
Rb較大,所以wa較大
wa-wb=根號(GM)(1/根號Ra-1/根號Rb)
當(dāng)a比b正好多轉(zhuǎn)一圈(2π度),a,b再重合,簡單的追擊問題邏輯
設(shè)t時間后B再次在A上方
t=2π/(wa-wb)=2π根號(RaRb)/{根號(GM)[根號(Rb)-根號(Ra)]}