運用了如下公式：log(a)(b)/log(a)(c)=log(c)(b)
log(a)(b)=ln(b)/ln(a)
log(a)(b)+log(a)(c)=log(a)(bc)謝謝··可能我沒把我的問題說清楚吧··我想問的是··log(3)(7)+3·log(3)(2)為什么會=ab+3而不是=b+3a··········log(3)(7)+log(3)(2)+1為什么會=ab+b+1而不是=b+a+1這樣吧，我?guī)湍阃茖б槐椋涸?log（3）（56)/log(3)(42)=(log(3)(7)+log(3)(8))/(log(3)(7)+log(3)(6))=(log(3)(7)+3log(3)(2))/(1og(3)(7)+log(3)(3)+log(3)(2))=(b+3/a)/(b+1+1/a)=(ab+3)/(ab+a+1)你說的log(3)(7)+3·log(3)(2)=b+3/a ·log(3)(7)+log(3)(2)+1=b+1+1/a再補充幾個公式：log(a)(b^k)=klog(a)(b)log(a)(b)=1/(log(b)(a))懂？