關(guān)于數(shù)學(xué)對(duì)數(shù)的換底公式推論的問題
已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)
因?yàn)閘og(2)(3)=a,則1/a=log(3)(2),又∵log(3)(7)=b,
∴l(xiāng)og(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
因?yàn)槲叶妓哪甓鄾]接觸過咯···完全忘咯原理是怎樣的···請(qǐng)高手幫幫忙仔細(xì)的講解一下下··謝謝··特別是log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/an+b+1···這里完全不明白用的是什么方法解的···剛剛申請(qǐng)的賬號(hào)··分比較少··請(qǐng)見諒···