如圖,在△ABC中,∠A=45°,邊AC的垂直平分線交邊AB于E點(diǎn),交CB的延長(zhǎng)線于點(diǎn)F,垂足為點(diǎn)D.如果AB=AC,求證:EC=EF.
如圖,在△ABC中,∠A=45°,邊AC的垂直平分線交邊AB于E點(diǎn),交CB的延長(zhǎng)線于點(diǎn)F,垂足為點(diǎn)D.如果AB=AC,求證:EC=EF.
![](http://hiphotos.baidu.com/zhidao/pic/item/279759ee3d6d55fbb7956e946e224f4a20a4dd34.jpg)
優(yōu)質(zhì)解答
證明:∵∠A=45°,AB=AC,
∴∠ABC=∠ACB=
(180°-∠A)=62.5°,
∵DE是AC的垂直平分線,
∴AE=CE,
∴∠ACE=∠A=45°,
∴∠ECB=62.5°-45°=17.5°,
∵DE是AC的垂直平分線,
∴∠EDA=90°,
∵∠A=45°,
∴∠AED=45°,
∴∠FDB=∠AED=45°,
∵∠ABC=62.5°,
∴∠F=∠ABC-∠FDB=17.5°,
∴∠F=∠ECB,
∴EC=EF.
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