一個英語的物理題,牛人請進(jìn)
昨天做題遇到一個物理題目,雖然不難但是難以理解,做不下來啊》》
望高手們予以回答：
An object is launched from the ground with an initial velocity and angle such that the maximum high height achieved is equal to the total range of the projectile.The tangent of the launch angle is equal:
A:1
B:2
C:3
D:4
E:5
At a launch angle of 45',the range of a launched prijectile is given by:
A:(Vi)^2/g
B:2(Vi)^2/g
C:(Vi)^2/2g
D:根號下[(Vi)^2/2g]
E:2Vi/g
歡迎英語牛人進(jìn)行翻譯,
最近積分用完了,我去儲儲.
正確,我看看有沒更詳細(xì)的.