不是鏈?zhǔn)椒▌t
鏈?zhǔn)椒▌t是 d/dx (f(g(x)) = f'(g(x)) * g'(x)
f(x)'=(x^3+3x+1)' =(x^3)'+(3x)'+(1)' =3x^2+3+0 = 3x^2+3 原理是 和的導(dǎo)數(shù) 等于 導(dǎo)數(shù)的和
求導(dǎo)四則運(yùn)算:
(u+v)' = u'+v'
(u-v)' = u'-v'
(u*v)' = u' * v + v' * u
(u/v)' = ( u' * v - v' * u) / (v^2)哦,你把商法則推導(dǎo)一下
f(x)=x^3+3x+1求導(dǎo),怎么弄
f(x)=x^3+3x+1求導(dǎo),怎么弄
f(x)'=(x^3+3x)'是這個嗎,為什么可以等于兩個函數(shù)的導(dǎo)數(shù)之和,是用鏈?zhǔn)椒▌t嗎,學(xué)高數(shù)第一天,說明白點(diǎn)
=(x^3)'+(3x)'
=2x^+3
順便說一下求導(dǎo)四則運(yùn)算的推導(dǎo)
f(x)'=(x^3+3x)'是這個嗎,為什么可以等于兩個函數(shù)的導(dǎo)數(shù)之和,是用鏈?zhǔn)椒▌t嗎,學(xué)高數(shù)第一天,說明白點(diǎn)
=(x^3)'+(3x)'
=2x^+3
順便說一下求導(dǎo)四則運(yùn)算的推導(dǎo)
數(shù)學(xué)人氣:290 ℃時間:2019-10-11 18:54:10
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