1.設(shè)a.b為實(shí)數(shù),試求a^2+2ab+2b^2-4a+7
1.設(shè)a.b為實(shí)數(shù),試求a^2+2ab+2b^2-4a+7
2.(a^2+b^2)^-2(a^2+b^2)-8=0 求a^2+b^2
3.a^2-3a+1=0 求4a^2-9a-2+9/(1+a^2)
2.(a^2+b^2)^2-2(a^2+b^2)-8=0 求a^2+b^2
1.設(shè)a.b為實(shí)數(shù),試求a^2+2ab+2b^2-4a+7的最小值
2.(a^2+b^2)^-2(a^2+b^2)-8=0 求a^2+b^2
3.a^2-3a+1=0 求4a^2-9a-2+9/(1+a^2)
2.(a^2+b^2)^2-2(a^2+b^2)-8=0 求a^2+b^2
1.設(shè)a.b為實(shí)數(shù),試求a^2+2ab+2b^2-4a+7的最小值
數(shù)學(xué)人氣:505 ℃時(shí)間:2019-11-20 05:18:08
優(yōu)質(zhì)解答
1.設(shè)a.b為實(shí)數(shù),試求a^2+2ab+2b^2-4a+7的最小值a^2+2ab+2b^2-4a+7=2(0.5a+b)^2+0.5(a-4)^2-1a^2+2ab+2b^2-4a+7的最小值是-12.(a^2+b^2)^-2(a^2+b^2)-8=0 求a^2+b^2(a^2+b^2+2)(a^2+b^2-4)=0a^2+b^2=43.a^2-3a...哈哈,我第三題正好會(huì)我第三題算的是3原式=4(a^2-3a+1)+3a-6+3/a =0+3a-6+3/a =3(a^2+1)/a-6 =9-6 =3原式=4(a^2-3a+1)+3a-6+3/a =0+3a-6+3/a =3(a^2-2a+1)/a =3*(a)/a=3\(^o^)/YES!√
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