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  • 幫我解一元一次方程組,急用~

    幫我解一元一次方程組,急用~
    1.3x+5y=15,
    2x-3y=-4.
    2.3分之x+4分之x=1,
    2x-3y=5
    3.x-2y-3=0
    5x+4y+8=0
    4.x-2y+3z=0
    3x+2y+5z=12
    2x-4y-z=-7
    5.2x-3y+4z=12
    x-y+3z=4
    4x+y-3z=-2
    6.x+2y+3z=15
    3分之x+4z=4分之y-3z=3
    數(shù)學人氣:438 ℃時間:2020-04-10 19:14:59
    優(yōu)質解答
    1.
    3x+5y = 15 …①
    2x-3y = -4 …②
    ①×3+②×5,得(3×3+2×5)x = 15×3+(-4)×5
    19x = 25
    x = 25/19
    代入①有,3×25/19 + 5y = 15
    y = (15-75/19)/5 = 3 - 15/19 = 42/19
    于是x=25/19,y=42/19.
    2.
    x/3 + y/4 =1 …①
    2x-3y = 5 …②
    ①×12+②,有(4+2)x = 17 于是x=17/6
    代入②,有2×17/6-3y = 5
    y = (17/3 - 5)/3 = 2/9
    于是x=17/6,y=2/9
    3.
    x-2y-3 = 0 ...①
    5x+4y+8 = 0 ...②
    ①×2+②,得7x+2=0,于是x=-2/7
    代入①,有y=(x-3)/2 = (-2/7-3)/2 = -23/14
    于是x=-2/7,y=-23/14.
    4.
    x-2y+3z = 0 .①
    3x+2y+5z = 12 ..②
    2x-4y-z = -7 ...③
    ①+②得,4x+8z = 12 ...④
    ②×2+③得,8x+9z = 17 ...⑤
    ④×2-⑤得,7z = 7,z=1
    代入④,有x = (12-8z)/4 = 3-2z = 1
    再把z=1,x=1代入①得
    y=(x+3z)/2 = 2
    于是x=1,y=2,z=1.
    5.
    2x-3y+4z=12 ...①
    x-y+3z=4 ...②
    4x+y-3z=-2 ...③
    ①-②×3,得-x-5z=0 ...④
    ②+③,得5x=2 x=2/5
    代入④,有 z = -1/5·x = -2/25
    將x=2/5,z=-2/25代入②,有
    y=x+3z-4 = 2/5 + 6/25 -4 = -84/25
    于是 x=2/5,y=-84/25,z=-2/25.
    6.
    x+2y+3z=15 ...①
    x/3+4z=3 ...②
    y/4-3z=3 ...③
    ①-③×8,得x+27z = -9 ...④
    ④-②×3,得15z = -18 ,z=-6/5
    代入④,有x=-9-27z = 117/5
    將z=-6/5代入③,有
    y = 4(3+3z) = -12/5
    于是x=117/5 ,y=-12/5,z=-6/5.
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