x1,x2是方程x方+3x+1=0的兩實(shí)數(shù)根,
即x1^2+3x1+1=0
x1^2+3x1=-1
x1^2=-3x1-1
根據(jù)韋達(dá)定理得x1+x2=-3
x1^3+8x2+20
=x1*x1^2+8x2+20
=x1*(-3x1-1)+8x2+20
=-3x1^2-x1+8x2+20
=-3x1^2-9x1+8x1+8x2+20
=-3(x1^2+3x1)+8(x1+x2)+20
=-3*(-1)+8*(-3)+20
=3-24+20
=-1