1. y=cosx單調(diào)減區(qū)間為 [2kπ,2kπ+π]
函數(shù)y=3cos(2x-π/3),x∈R的單調(diào)區(qū)間
2kπ<=2x-π/3<=2kπ+π 解得
單調(diào)減區(qū)間 【kπ+π/6,kπ+2π/3】
y=cosx單調(diào)增減區(qū)間為 [2kπ-π,2kπ]
函數(shù)y=3cos(2x-π/3),x∈R的單調(diào)增區(qū)間
2kπ-π<=2x-π/3<=2kπ 解得
單調(diào)增區(qū)間 【kπ-2π/3,kπ+π/6】
2.y=sinx單調(diào)增區(qū)間為 [2kπ-π/2,2kπ+π/2]
函數(shù)y=sin(-3x+π/4)=-sin(3x-π/4)
函數(shù)y=sin(-3x+π/4)=-sin(3x-π/4)單調(diào)減區(qū)間為
2kπ-π/2<=3x-π/4<=2kπ+π/2
單調(diào)減區(qū)間為【2kπ/3-π/12,2kπ/3+3π/12】
y=sinx單調(diào)減區(qū)間為 [2kπ+π/2,2kπ+3π/2]
函數(shù)y=sin(-3x+π/4)=-sin(3x-π/4)單調(diào)增區(qū)間為
2kπ+π/2<=3x-π/4<=2kπ+3π/2
單調(diào)增區(qū)間為【2kπ/3+3π/12,2kπ/3+7π/12】
πππ