9x+(a+13)/x>=a+1對x>0恒成立,
a(1-1/x)1時a=6√21,當x=1+√21/3時取等號,
∴a
函數(shù)9x加x分之a(chǎn)方加13,若該函數(shù)大于等于a加1對一切x大于等于0恒成立,求a取值范圍
函數(shù)9x加x分之a(chǎn)方加13,若該函數(shù)大于等于a加1對一切x大于等于0恒成立,求a取值范圍
數(shù)學人氣:405 ℃時間:2020-04-21 14:38:55
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