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  • 化簡 sin(π/2+a)cos(π/2-a)/cos(3π/2-a)sin(3π/2+a)

    化簡 sin(π/2+a)cos(π/2-a)/cos(3π/2-a)sin(3π/2+a)
    2) sin25π/6+cos25π/3+tan(-25π/4)
    數(shù)學人氣:765 ℃時間:2020-06-02 19:08:00
    優(yōu)質(zhì)解答
    sin(π/2+a)cos(π/2-a)/cos(3π/2-a)sin(3π/2+a)
    =(cosasina)/(-sinα*-cosα)
    =1
    sin25π/6+cos25π/3+tan(-25π/4)
    =sinπ/6+cosπ/3+tan(-π/4)
    =1/2+1/2-1
    =0
    sin(2kπ+α)=sinα
    cos(2kπ+α)=cosα
    tan(2kπ+α)=tanα
    cot(2kπ+α)=cotα
    sec(2kπ+α)=secα
    csc(2kπ+α)=cscα
    sin(π+α)=-sinα
    cos(π+α)=-cosα
    tan(π+α)=tanα
    cot(π+α)=cotα
    sec(π+α)=-secα
    csc(π+α)=-cscα
    sin(-α)=-sinα
    cos(-α)=cosα
    tan(-α)=-tanα
    cot(-α)=-cotα
    sec(-α)=secα
    csc(-α)=-cscα
    sin(π-α)=sinα
    cos(π-α)=-cosα
    tan(π-α)=-tanα
    cot(π-α)=-cotα
    sec(π-α)=-secα
    csc(π-α)=cscα
    sin(α-π)=-sinα
    cos(α-π)=-cosα
    tan(α-π)=tanα
    cot(α-π)=cotα
    sec(α-π)=-secα
    csc(α-π)=-cscα
    sin(2π-α)=-sinα
    cos(2π-α)=cosα
    tan(2π-α)=-tanα
    cot(2π-α)=-cotα
    sec(2π-α)=secα
    csc(2π-α)=-cscα
    sin(π/2+α)=cosα
    cos(π/2+α)=-sinα
    tan(π/2+α)=-cotα
    cot(π/2+α)=-tanα
    sec(π/2+α)=-cscα
    csc(π/2+α)=secα
    sin(π/2-α)=cosα
    cos(π/2-α)=sinα
    tan(π/2-α)=cotα
    cot(π/2-α)=tanα
    sec(π/2-α)=cscα
    csc(π/2-α)=secα
    sin(3π/2+α)=-cosα
    cos(3π/2+α)=sinα
    tan(3π/2+α)=-cotα
    cot(3π/2+α)=-tanα
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