在如圖所示電路中,R
1=20Ω,當(dāng)開(kāi)關(guān)S、S
1都合上時(shí)電流表示數(shù)為0.3A,當(dāng)開(kāi)關(guān)S合上、S
1斷開(kāi)時(shí)電流表示數(shù)為0.1A,求R
2的阻值.
![](http://hiphotos.baidu.com/zhidao/pic/item/54fbb2fb43166d220939cf25452309f79052d231.jpg)
由題意可知當(dāng)兩個(gè)開(kāi)關(guān)都閉合時(shí),經(jīng)過(guò)R
1的電流
I
1=I-I
2=0.3A-0.1A=0.2A,
R
1兩端的電壓U
1=I
1R
1=0.2A×20Ω=4V,
可知U
2=U
1=4V
所以R
2的阻值R
2=
=
=40Ω.
答:R
2的阻值為40Ω