∵復(fù)數(shù)z滿足|z-1|=|z-i|，
∴|x-1+yi|=|x+（y-1）i|
∴
| (x?1)2+y2 |
| x2+(y?1)2 |
化為x-y=0．
故答案為：x-y=0．
復(fù)數(shù)z滿足|z-1|=|z-i|，則此復(fù)數(shù)z所對(duì)應(yīng)的點(diǎn)的軌跡方程是_．
復(fù)數(shù)z滿足|z-1|=|z-i|，則此復(fù)數(shù)z所對(duì)應(yīng)的點(diǎn)的軌跡方程是______．
數(shù)學(xué)人氣：604 ℃時(shí)間：2020-06-02 12:14:34
優(yōu)質(zhì)解答
令z=x+yi（x，y∈R）．
∵復(fù)數(shù)z滿足|z-1|=|z-i|，
∴|x-1+yi|=|x+（y-1）i|
∴
＝
，
化為x-y=0．
故答案為：x-y=0．
∵復(fù)數(shù)z滿足|z-1|=|z-i|，
∴|x-1+yi|=|x+（y-1）i|
∴
化為x-y=0．
故答案為：x-y=0．
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